Recent content by help I have 12 hours

Yes, I have done this. I found the f(obs) = (5.1189*10^14)hz and then I "un-shifted" to find the f(source)=(3.19675*10^15)hz which gave me lambda=94nm for the source light, but when I use the Rydberg equation from there I get a nonsense answer. Sorry, but can someone check if the problem has an...

I found the observed frequency from the energy. Then I used the receding Doppler shift formula to find, the source frequency but after that when i tried to use the Rydberg equation I got a value for the energy level less than one. and I'm pretty sure my work is right, any help is greatly...

(d)sin(40.6)=(475*10^-9)(1) d=730*10^-9 (m) prof says answer is 1460*10^-9 (m) tho

where x is the distance from one speaker 343=(66)(5.197) wave length =5.197m x-(50-x)=(5.197)(m+0.5) I choose m=-10 2x-50=(5.197)(-9.5) x=0.314m? Prof says correct answer is 1.6m tho

or get me very close to the answer, cus I'm not getting it and i don't have time to get it. thank you

thank you I'm very busy and confused, can you tell me the answer?

if the distance from the object to the objective lens is .2 cm. How does 1/s+1/s'=1/f? 1/.2+1/22.2=1/.2 ?

How do I find the image distance of the objective if I don't know where the objective is? Thanks

what is thank you

angular magnification=9.62 part a 1/s+1/s'=5 1/(25-s-s')+1/s"=1/2.6 -s"/s=m can't find m, don't know how to use the info that a person of normal eyesight is looking into the microscope.

thank you, I got it.

cos(theta)=c/vn cos(1.2 degrees)=((3*10^8)/v(1.03)) v=291262135.9 v/c=.971 so the particle is moving at (.971)c But mastering physics tells me this is wrong, and says that I'm not account for the angle. I am really stumped.