Recent content by dainceptionman_02

but Halliday still wrote it in the way that i showed in the original post...

this formula is missing the cosine of the angle in one dimension

i'm copying from the book... Hookes Law - F = -kx W = Fdcos∅ since ∅ is 180°, W = -Fd = -Fx W = ∫(-Fxdx) now the book says, from Hookes Law equation "the force magnitude F is kx. Thus, substitution leads to W = ∫(-kxdx)" why are they saying to substitute the magnitude of the force and not the...

lol, well it does get stuck in the ground. it is a volcano launching a rock that "lands" at the base of the mountain.

the final velocity is zero in the x and y-direction for this particular situation. shouldn't that equation work?

the answer to this question uses the above formula with the tangent function and solves for the initial velocity, i used the equation (v.sinθ^2) = (v.sinθ)^2 - 2gΔy, setting final velocity equal to zero and solving for initial velocity. this kinematic equation gives a different answer. can...

forgive me, i don't have an instructor to beat this answer into me

so on Earth, the viewers would have to set a wait time at 2.3 years for this to finish?

i have just started on relativity, so be simple. you are going to travel 1 lightyear at half the speed of light. therefore, it would take 2 years to travel 1 lightyear. on Earth, you would see me going half the speed of light, so it should take two years as well? i calculated gamma as being...

whoops, i just noticed the question states a region, but not in a conducting loop or geometry.

but changing the area or rotating the loop does induce a voltage therefore it should induce an electric field? there is the statement that a changing magnetic field induces an electric field, but couldn't an electric field also be induced by changing the area or angle, aka magnetic flux?

TL;DR Summary: A (nonconservative electric field is induced in any region in which) A. there is a changing magnetic flux B. there is a changing magnetic field C. the inductive time constant is large D. the electrical resistance is small E. there is electrical current there can be more than one...

so the instantaneous emf is the amplitude, or ωNBA?

i have never seen this before! what do i do, or how do i set it up? thanks!

there are a bunch of problems in this section that ask similar questions, but they ask the amplitude and this doesn't. this is an even problem so i do not have the answer, but my hunch is that it is not an amplitude question. i solved for the amplitude so i am guessing i got this one wrong...