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Aurelius120's latest activity
A
Aurelius120
replied to the thread
Oil enters a bend in a pipe -- calculate the force needed to steady bend
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##P_2A_2 cos37##? Since force perpendicular to area is taken?
Saturday, 5:58 AM
A
Aurelius120
replied to the thread
Oil enters a bend in a pipe -- calculate the force needed to steady bend
.
The fluid flows horizontally in ##+\hat i## upto bend so force on it must be in direction of its velocity to make it flow and its...
Saturday, 3:27 AM
A
Aurelius120
replied to the thread
Oil enters a bend in a pipe -- calculate the force needed to steady bend
.
Reaction forces due to oil pressure: $$\vec F_1=P_1A_1 \hat i=-56\times 10^3\hat i$$ $$\vec F_2=P_2A_2=(8.6\times 10^3) \cos37\hat...
Saturday, 2:41 AM
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Aurelius120
posted the thread
Oil enters a bend in a pipe -- calculate the force needed to steady bend
in
Introductory Physics Homework Help
.
The pressure is easily calculated from equation of continuity and Bernoullis theorem: $$A_1v_1=A_2v_2\implies v_2=16ms^{-1}$$ SInce pipe...
Saturday, 1:40 AM
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Aurelius120
replied to the thread
Equation of hyperbola confocal with ellipse having same principal axes
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Also just to clarify more than one options are correct so all need to be checked
May 15, 2024
A
Aurelius120
posted the thread
Equation of hyperbola confocal with ellipse having same principal axes
in
Precalculus Mathematics Homework Help
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The equation of ellipse reduces to : $$(2x+3)^2+(3y+2)^2=8$$ $$\frac{(x+3/2)^2}{8/4}+\frac{(y+2/3)^2}{8/9}=1$$ Center of ellipse...
May 15, 2024
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Aurelius120
replied to the thread
Electric field & force due to charged insulating hemispherical shells
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Solution 1 Solution 2 Solution 3
May 9, 2024
A
Aurelius120
replied to the thread
Electric field & force due to charged insulating hemispherical shells
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The book's answer is option C though and the solution on the web is as described in the 1st post by somehow using the formula of...
May 8, 2024
A
Aurelius120
posted the thread
Electric field & force due to charged insulating hemispherical shells
in
Introductory Physics Homework Help
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So I know I have to equate force on a hemispherical shell with spring force to get value of compression but I can't find the force on...
May 8, 2024
A
Aurelius120
reacted to
haruspex's post
in the thread
A vertical U tube rotates about the vertical axis -- Find omega to cause this height offset
with
Like
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It is just like gravity, except that it is horizontal and varies along the length of the tube. Suppose the horizontal tube were to vary...
May 8, 2024
A
Aurelius120
replied to the thread
A vertical U tube rotates about the vertical axis -- Find omega to cause this height offset
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But isn't it equating the force required for rotation to force exerted? I don't know if there is something like Centripetal pressure...
May 8, 2024
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Aurelius120
replied to the thread
A vertical U tube rotates about the vertical axis -- Find omega to cause this height offset
.
I am not sure I understand. The water can't be treated as rectangular/cylindrical blocks with forces ##V\rho g## on either side and...
May 8, 2024
A
Aurelius120
replied to the thread
A vertical U tube rotates about the vertical axis -- Find omega to cause this height offset
.
I think I got it $$\int^b_0{\omega^2 A\rho rdr}-PA=A(b)\rho g$$ $$\int^{2b}_0{\omega^2A\rho rdr}-PA=A(3b)\rho g$$ Therefore Subtracting...
May 8, 2024
A
Aurelius120
replied to the thread
A vertical U tube rotates about the vertical axis -- Find omega to cause this height offset
.
So how do I account for that? Its arbitrary so how to know its value
May 7, 2024
A
Aurelius120
replied to the thread
A vertical U tube rotates about the vertical axis -- Find omega to cause this height offset
.
So it will be $$\int{\omega^2r dm}= V\rho g$$ On either side with limits ##0\text{ to }b## and ##0\text{ to }2b## and ##V## changed...
May 7, 2024
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